CF #284 Div1 C Array and Operations
問題を読むと明らかにフローだし辺の張り方が明らかに二部グラフだし…
本当にフロー流すだけ問題。
#include <iostream> #include <cstdio> #include <complex> #include <set> #include <vector> #include <stack> #include <tuple> #include <algorithm> #include <cassert> #include <cstring> #include <queue> using namespace std; typedef long long ll; typedef pair<int, int> P; template<int V> struct MaxFlow { using T = int; const T INF = 1<<28; struct Edge { int to, rev; T cap; }; vector<Edge> g[V]; int level[V]; int iter[V]; void add(int from, int to, T cap) { if (!cap) return; g[from].push_back(Edge{to, (int)g[to].size(), cap}); g[to].push_back(Edge{from, (int)g[from].size()-1, 0}); } void add_multi(int from, int to, T cap) { g[from].push_back(Edge{to, (int)g[to].size(), cap}); g[to].push_back(Edge{from, (int)g[from].size()-1, cap}); } void bfs(int s) { fill_n(level, V, -1); queue<int> que; level[s] = 0; que.push(s); while (!que.empty()) { int v = que.front(); que.pop(); for (Edge e: g[v]) { if (e.cap <= 0) continue; if (level[e.to] < 0) { level[e.to] = level[v] + 1; que.push(e.to); } } } } T dfs(int v, int t, T f) { if (v == t) return f; for (int &i = iter[v]; i < g[v].size(); i++) { Edge &e = g[v][i]; if (e.cap <= 0) continue; if (level[v] < level[e.to]) { T d = dfs(e.to, t, min(f, e.cap)); if (d <= 0) continue; e.cap -= d; g[e.to][e.rev].cap += d; return d; } } return 0; } T exec(int s, int t) { T flow = 0; while (true) { bfs(s); if (level[t] < 0) return flow; fill_n(iter, V, 0); T f; while ((f = dfs(s, t, INF)) > 0) { flow += f; } } } }; const int MN = 210; int main() { int n, m; cin >> n >> m; int a[MN]; vector<P> mv; set<int> s; for (int i = 0; i < n; i++) { cin >> a[i]; int b = a[i]; for (int j = 2; j*j <= a[i]; j++) { if (b % j == 0) s.insert(j); while (b % j == 0) { b /= j; } } if (b > 1) s.insert(b); } for (int i = 0; i < m; i++) { int a, b; cin >> a >> b; a--; b--; if (a % 2 == 1) swap(a, b); mv.push_back(P(a, b)); } vector<int> v(s.begin(), s.end()); int vs = n, vt = vs+1; int res = 0; for (int d: v) { MaxFlow<MN> mf; for (P p: mv) { mf.add(p.first, p.second, 100000); } for (int i = 0; i < n; i += 2) { int u = 0; while (a[i] % d == 0) { u++; a[i] /= d; } mf.add(vs, i, u); } for (int i = 1; i < n; i += 2) { int u = 0; while (a[i] % d == 0) { u++; a[i] /= d; } mf.add(i, vt, u); } res += mf.exec(vs, vt); } cout << res << endl; return 0; }